3.845 \(\int \frac {1}{x^8 \sqrt {a-b x^4}} \, dx\)

Optimal. Leaf size=102 \[ \frac {5 b^{7/4} \sqrt {1-\frac {b x^4}{a}} F\left (\left .\sin ^{-1}\left (\frac {\sqrt [4]{b} x}{\sqrt [4]{a}}\right )\right |-1\right )}{21 a^{7/4} \sqrt {a-b x^4}}-\frac {5 b \sqrt {a-b x^4}}{21 a^2 x^3}-\frac {\sqrt {a-b x^4}}{7 a x^7} \]

[Out]

-1/7*(-b*x^4+a)^(1/2)/a/x^7-5/21*b*(-b*x^4+a)^(1/2)/a^2/x^3+5/21*b^(7/4)*EllipticF(b^(1/4)*x/a^(1/4),I)*(1-b*x
^4/a)^(1/2)/a^(7/4)/(-b*x^4+a)^(1/2)

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Rubi [A]  time = 0.03, antiderivative size = 102, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.188, Rules used = {325, 224, 221} \[ \frac {5 b^{7/4} \sqrt {1-\frac {b x^4}{a}} F\left (\left .\sin ^{-1}\left (\frac {\sqrt [4]{b} x}{\sqrt [4]{a}}\right )\right |-1\right )}{21 a^{7/4} \sqrt {a-b x^4}}-\frac {5 b \sqrt {a-b x^4}}{21 a^2 x^3}-\frac {\sqrt {a-b x^4}}{7 a x^7} \]

Antiderivative was successfully verified.

[In]

Int[1/(x^8*Sqrt[a - b*x^4]),x]

[Out]

-Sqrt[a - b*x^4]/(7*a*x^7) - (5*b*Sqrt[a - b*x^4])/(21*a^2*x^3) + (5*b^(7/4)*Sqrt[1 - (b*x^4)/a]*EllipticF[Arc
Sin[(b^(1/4)*x)/a^(1/4)], -1])/(21*a^(7/4)*Sqrt[a - b*x^4])

Rule 221

Int[1/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> Simp[EllipticF[ArcSin[(Rt[-b, 4]*x)/Rt[a, 4]], -1]/(Rt[a, 4]*Rt[
-b, 4]), x] /; FreeQ[{a, b}, x] && NegQ[b/a] && GtQ[a, 0]

Rule 224

Int[1/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> Dist[Sqrt[1 + (b*x^4)/a]/Sqrt[a + b*x^4], Int[1/Sqrt[1 + (b*x^4)
/a], x], x] /; FreeQ[{a, b}, x] && NegQ[b/a] &&  !GtQ[a, 0]

Rule 325

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[((c*x)^(m + 1)*(a + b*x^n)^(p + 1))/(a*
c*(m + 1)), x] - Dist[(b*(m + n*(p + 1) + 1))/(a*c^n*(m + 1)), Int[(c*x)^(m + n)*(a + b*x^n)^p, x], x] /; Free
Q[{a, b, c, p}, x] && IGtQ[n, 0] && LtQ[m, -1] && IntBinomialQ[a, b, c, n, m, p, x]

Rubi steps

\begin {align*} \int \frac {1}{x^8 \sqrt {a-b x^4}} \, dx &=-\frac {\sqrt {a-b x^4}}{7 a x^7}+\frac {(5 b) \int \frac {1}{x^4 \sqrt {a-b x^4}} \, dx}{7 a}\\ &=-\frac {\sqrt {a-b x^4}}{7 a x^7}-\frac {5 b \sqrt {a-b x^4}}{21 a^2 x^3}+\frac {\left (5 b^2\right ) \int \frac {1}{\sqrt {a-b x^4}} \, dx}{21 a^2}\\ &=-\frac {\sqrt {a-b x^4}}{7 a x^7}-\frac {5 b \sqrt {a-b x^4}}{21 a^2 x^3}+\frac {\left (5 b^2 \sqrt {1-\frac {b x^4}{a}}\right ) \int \frac {1}{\sqrt {1-\frac {b x^4}{a}}} \, dx}{21 a^2 \sqrt {a-b x^4}}\\ &=-\frac {\sqrt {a-b x^4}}{7 a x^7}-\frac {5 b \sqrt {a-b x^4}}{21 a^2 x^3}+\frac {5 b^{7/4} \sqrt {1-\frac {b x^4}{a}} F\left (\left .\sin ^{-1}\left (\frac {\sqrt [4]{b} x}{\sqrt [4]{a}}\right )\right |-1\right )}{21 a^{7/4} \sqrt {a-b x^4}}\\ \end {align*}

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Mathematica [C]  time = 0.01, size = 52, normalized size = 0.51 \[ -\frac {\sqrt {1-\frac {b x^4}{a}} \, _2F_1\left (-\frac {7}{4},\frac {1}{2};-\frac {3}{4};\frac {b x^4}{a}\right )}{7 x^7 \sqrt {a-b x^4}} \]

Antiderivative was successfully verified.

[In]

Integrate[1/(x^8*Sqrt[a - b*x^4]),x]

[Out]

-1/7*(Sqrt[1 - (b*x^4)/a]*Hypergeometric2F1[-7/4, 1/2, -3/4, (b*x^4)/a])/(x^7*Sqrt[a - b*x^4])

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fricas [F]  time = 0.94, size = 0, normalized size = 0.00 \[ {\rm integral}\left (-\frac {\sqrt {-b x^{4} + a}}{b x^{12} - a x^{8}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^8/(-b*x^4+a)^(1/2),x, algorithm="fricas")

[Out]

integral(-sqrt(-b*x^4 + a)/(b*x^12 - a*x^8), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\sqrt {-b x^{4} + a} x^{8}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^8/(-b*x^4+a)^(1/2),x, algorithm="giac")

[Out]

integrate(1/(sqrt(-b*x^4 + a)*x^8), x)

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maple [A]  time = 0.02, size = 109, normalized size = 1.07 \[ \frac {5 \sqrt {-\frac {\sqrt {b}\, x^{2}}{\sqrt {a}}+1}\, \sqrt {\frac {\sqrt {b}\, x^{2}}{\sqrt {a}}+1}\, b^{2} \EllipticF \left (\sqrt {\frac {\sqrt {b}}{\sqrt {a}}}\, x , i\right )}{21 \sqrt {\frac {\sqrt {b}}{\sqrt {a}}}\, \sqrt {-b \,x^{4}+a}\, a^{2}}-\frac {5 \sqrt {-b \,x^{4}+a}\, b}{21 a^{2} x^{3}}-\frac {\sqrt {-b \,x^{4}+a}}{7 a \,x^{7}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/x^8/(-b*x^4+a)^(1/2),x)

[Out]

-1/7*(-b*x^4+a)^(1/2)/a/x^7-5/21*b*(-b*x^4+a)^(1/2)/a^2/x^3+5/21/a^2*b^2/(1/a^(1/2)*b^(1/2))^(1/2)*(-1/a^(1/2)
*b^(1/2)*x^2+1)^(1/2)*(1/a^(1/2)*b^(1/2)*x^2+1)^(1/2)/(-b*x^4+a)^(1/2)*EllipticF((1/a^(1/2)*b^(1/2))^(1/2)*x,I
)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\sqrt {-b x^{4} + a} x^{8}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^8/(-b*x^4+a)^(1/2),x, algorithm="maxima")

[Out]

integrate(1/(sqrt(-b*x^4 + a)*x^8), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {1}{x^8\,\sqrt {a-b\,x^4}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x^8*(a - b*x^4)^(1/2)),x)

[Out]

int(1/(x^8*(a - b*x^4)^(1/2)), x)

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sympy [A]  time = 1.40, size = 46, normalized size = 0.45 \[ \frac {\Gamma \left (- \frac {7}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {7}{4}, \frac {1}{2} \\ - \frac {3}{4} \end {matrix}\middle | {\frac {b x^{4} e^{2 i \pi }}{a}} \right )}}{4 \sqrt {a} x^{7} \Gamma \left (- \frac {3}{4}\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x**8/(-b*x**4+a)**(1/2),x)

[Out]

gamma(-7/4)*hyper((-7/4, 1/2), (-3/4,), b*x**4*exp_polar(2*I*pi)/a)/(4*sqrt(a)*x**7*gamma(-3/4))

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